Algoritmlarni loyiyalash fani bo’yicha laboratoriya ishi-3 Bajarildi

O`ZBEKISTON RESPUBLIKASI AXBOROT TEXNOLOGIYALARI VA KOMMUNIKATSIYALARNI RIVOJLANTIRISH VAZIRLIGI MUHAMMAD AL-XORAZMIY NOMIDAGI TOSHKENT AXBOROT TEXNOLOGIYALAR UNIVERSITETI

ALGORITMLASH VA MATEMATIK MODELLASHTIRISH KAFEDRASI

ALGORITMLARNI LOYIYALASH FANI BO’YICHA
LABORATORIYA ISHI-3

Bajarildi:
2-kurs talabasi
CAL008-L1 - guruh
Begmatov J.

Tekshirildi:
Aliqulov Y.Q.


Toshkent – 2022
Jadval ko’rinishida berilgan funktsiyalar uchun eng kichik kvadratlar usuli. Empirik bog’lanish qonunlarining chiziqli va kvadratik modeli
1.Eng kichik kvadratlar usuli yordamida chiziqli modelni C++ dasturlash tilida aniqlang.
12-variant

Y	X
0.526	0.41
0.453	0.46
0.482	0.52
0.552	7.64893
0.436	7.36235
0.378	7.09613

Dastur kodi:
#include
using namespace std;
int main()
{
double a0, a1, x[10], y[10], sum1, sum2, sum3, sum4;
for (int i = 0; i <= 6; i++)
{
cout << "x[" << i << "]= "; cin >> x[i]; cout << endl;
sum1 += x[i];
sum3 += x[i] * x[i];
}
for (int i = 0; i <= 6; i++)
{
cout << "y[" << i << "]= "; cin >> y[i]; cout << endl;
sum2 += y[i];
sum4 += y[i] * x[i];
}
cout << "x summa = " << sum1 << endl;
cout << "x*x summa = " << sum2 << endl;
cout << "y summa = " << sum3 << endl;
cout << "x*y summa = " << sum4 << endl << endl;
a1 = (sum2 * sum3 - sum1 * sum4) / (8 * sum3 - sum1 * sum1);
a0 = (sum4 - sum1 * a1) / sum3;

cout << "y = " << a0 << "x + " << a1;}

Natija:___2.Eng_kichik_kvadratlar_usuli_yordamida_kvadratik_modelni_C++_dasturlash_tilida_aniqlang._Dastur_kodi'>Natija:


2.Eng kichik kvadratlar usuli yordamida kvadratik modelni C++ dasturlash tilida aniqlang.
Dastur kodi:
#include
using namespace std;
double determinantOfMatrix(double mat[3][3])
{
double ans;
ans = mat[0][0] * (mat[1][1] * mat[2][2] - mat[2][1] * mat[1][2])
- mat[0][1] * (mat[1][0] * mat[2][2] - mat[1][2] * mat[2][0])
+ mat[0][2] * (mat[1][0] * mat[2][1] - mat[1][1] * mat[2][0]);
return ans;
}
void findSolution(double coeff[3][4])
{
double d[3][3] = {
{ coeff[0][0], coeff[0][1], coeff[0][2] },
{ coeff[1][0], coeff[1][1], coeff[1][2] },
{ coeff[2][0], coeff[2][1], coeff[2][2] },
};
double d1[3][3] = {
{ coeff[0][3], coeff[0][1], coeff[0][2] },
{ coeff[1][3], coeff[1][1], coeff[1][2] },
{ coeff[2][3], coeff[2][1], coeff[2][2] },
};
double d2[3][3] = {
{ coeff[0][0], coeff[0][3], coeff[0][2] },
{ coeff[1][0], coeff[1][3], coeff[1][2] },
{ coeff[2][0], coeff[2][3], coeff[2][2] },
};
double d3[3][3] = {
{ coeff[0][0], coeff[0][1], coeff[0][3] },
{ coeff[1][0], coeff[1][1], coeff[1][3] },
{ coeff[2][0], coeff[2][1], coeff[2][3] },
};
double D = determinantOfMatrix(d);
double D1 = determinantOfMatrix(d1);
double D2 = determinantOfMatrix(d2);
double D3 = determinantOfMatrix(d3);
if (D != 0) {
double x = D1 / D;
double y = D2 / D;
double z = D3 / D;
printf("Value of x is : %lf\n", x);
printf("Value of y is : %lf\n", y);
printf("Value of z is : %lf\n", z);
}
else {
if (D1 == 0 && D2 == 0 && D3 == 0)
printf("Infinite solutions\n");
else if (D1 != 0 || D2 != 0 || D3 != 0)
printf("No solutions\n");
}
}
int main()
{
double a[10], b[10], sum1, sum2, sum3, sum4, sum5, sum6, sum7;
for(int i=0; i<6; i++)
{
cout<<"x["<>a[i]; cout<sum1+=a[i];
sum3+=a[i]*a[i];
sum4+=a[i]*a[i]*a[i];
sum7+=a[i]*a[i]*a[i]*a[i];
}
for(int i=0; i<6; i++)
{
cout<<"y["<>b[i]; cout<sum2+=b[i];
sum5+=a[i]*b[i];
sum6+=a[i]*a[i]*b[i];
}
cout<<"x summa = "<cout<<"x*x summa = "<cout<<"x kub summa = "<cout<<"x 4-daraja summa = "<cout<<"y summa = "<cout<<"y*x summa = "<cout<<"x*x*y summa = "<double coeff[3][4] = {
{ sum7, sum4, sum3, sum6 },
{ sum4, sum3, sum1, sum5 },
{ sum3, sum1, 6, sum2 },
};
findSolution(coeff);
return 0;
}
Natija:

3.Topilgan modellarni tahlil qiling.
Dastur kodi:
#include
using namespace std;
int main ()
{
double x[10], f[10], y[10], y1[10], res;
for(int i=0; i<6; i++)
{
cout<<"x["<>x[i]; cout<}
for(int i=0; i<6; i++)
{
cout<<"f["<>f[i]; cout<}
for(int i=0; i<6; i++)
{
y[i]=10.6386*x[i]+0.0196839;
cout<<"y["<}
cout<<"CHIZIQLI MODEL TAHLILI :"<for(int i=0; i<6; i++)
{
res=fabs(f[i]-y[i]);
cout<}
cout<cout<<"KVADRATIK MODEL TAHLILI :"<for(int i=0; i<6; i++)
{
y1[i]=-142.142857*x[i]*x[i]+35.412143*x[i]-0.811307;
cout<<"y["<}
for(int i=0; i<6; i++)
{
res=fabs(f[i]-y1[i]);
cout<}


Natija: