ta son berilgan. Nechtasi musbat va nechtasi manfiyligini aniqlovchi dastur tuzing



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Komilov Javohir dasturlash


O’ZBEKISTON RESPUBLIKASI

OLIY VA O’RTA MAXSUS TA’LIM VAZIRLIGI


MIRZO ULUG’BEK NOMIDAGI

O’ZBEKISTON MILLIY UNIVERSITETI
MATEMATIKA fakulteti

MATEMATIKA yo’nalishi


21-04M GURUHI TALABASI

Komilov Javohirning

DASTURLASH ASOSLARI FANIDAN
MUSTAQIL ISHI

Topshirdi: Komilov Javohir

Qabul qildi: Muxlisa Olimova

Toshkent – 2021

1. 5 ta son berilgan. Nechtasi musbat va nechtasi manfiyligini aniqlovchi dastur tuzing.

#include

using namespace std;

int main()

{

int a,b,c,d,e,mus=0,man=0;



cin>>a>>b>>c>>d>>e;

if (a>0) {

mus++;

}

if (b>0) {



mus++;

}

if (c>0) {



mus++;

}

if (d>0) {



mus++;

}

if (e>0) {



mus++;

}

if (a<0){



man++;

}

if (b<0){



man++;

}

if (c<0){



man++;

}

if (d<0){



man++;

}

if (e<0){



man++;

}

cout<<"musbat: "<

return 0;

}

2. x>0,3 da y =sin2x-cos2x



X<=0,3 da y= 1/(x2-x1/2)

#include

#include

using namespace std;

int main()

{

float x,y;



cin>>x;

if (x>0,3) {

y=pow(sin(2*x),2)-pow(cos(x),2);

}

else {



y=1/(pow(x,2)-sqrt(x));

}

cout<

return 0;

}

3. (sin1/cos1)*((sin1+sin2)/(cos1+cos2))*……… *((sin1+sin2+….+sinn)/(cos1+cos2+….+cosn))



#include

#include

using namespace std;

int main()

{

int n;


float s1=0,p1=1,s2=0,p2=1;

cin>>n;


for (int i=1; is1=s1+sin(i);

p1=p1*s1;

}

for (int i=1; i

s2=s2+cos(i);

p2=p2*s2;

}

cout<


return 0;

}

4. 3ta son berilgan. Ularning o`rtacahsini toping.



#include

using namespace std;

int main()

{

int a,b,c;



cin>>a>>b>>c;

if (a>b) {

if (c>a) {

cout<


}

else if (b>c){

cout<

}

else {



cout<

}

}



else {

if (c>b) {

cout<

}

else if (a>c){



cout<

}

else {



cout<

}

}



return 0;

}

5. 1,1-1,2+1,3+…… ifodaning qiymatini toping.



n ta qo`shiluvchi bor.

#include

using namespace std;

int main()

{

int n;


double s=0.0;

cin>>n;


for (float i=1; is=s+1+i/10;

}

for (float i=2; i

s=s-1-i/10;

}

cout<

return 0;

}

6.



#include

#include

using namespace std;

int main()

{

float x,y,z,f;



cin>>x>>y>>z;

f=pow(y+pow(x-1,1/3),1/4)/(fabs(x-y)*(sin(z)*sin(z)+tan(x)));

cout<

return 0;

}

7. 1+1/2+...1/n>=a a berilgan n ning eng kichik qiymatini toping.



#include

#include

using namespace std;

int main()

{

int k;


float a,s=0,i=1;

cin>>a;


while(ss=s+1/i;


i++;

}

cout<

return 0;

}

8.Uch xonali son berilgan. Bu sonni barcha raqamlari turlichaligiga tekshiring.



#include

using namespace std;

int main()

{

int n;



cin>>n;

if(n/100!=n%10 && n%10!=(n%100)/10 && n/100!=(n%100)/10){

cout<< "barcha raqamlar turlicha";

}

else {



cout<< "barcha raqamlar turlicha emas";

}

return 0;



}
9.Sonni juft-toqligini va musbat-manfiyligini tekshiring.

#include


using namespace std;
int main()

{

int n;



cin>>n;

if (n>0) {

if(n%2==0){

cout<<"musbat juft";

}

else {


cout<<"musbat toq";

}

}



else if (n<0) {

if(n%2==0){

cout<<"manfiy juft";

}

else {



cout<<"manfiy toq";

}

}



else {

cout<<"nolga teng";

}
return 0;

}
10.Kesmada a va b berilgan. Shu ab ni n ta teng bolakka bolingan. Hosil bolgan nuqtalarni toping.

#include
using namespace std;
int main()

{

int n,a,b;



cin>>n>>a>>b;

for(int i=1; i

cout<

}

return 0;



}
11.n+1>0 bolsa y=m*m*n+1-c; n+1<=0 bolsa y=(m+n)*(m+n)+c*m*m; y=?

#include

using namespace std;
int main()

{

int m,n,c,y;



cin>>m>>n>>c;

if(n+1>0){

y=m*m*n+1-c;

}

else {



y=(m+n)*(m+n)+c*m*m;

}

cout<

return 0;

}
12.(1+1/1^2)(1+1/2^2)…(1+1/n^2)=?

#include

using namespace std;


int main()

{

int n;



float p=1;

cin>>n;


for(float i=1; ip=p*(1+1/(i*i));

}

cout<


return 0;

}
13.Agar son Musbat bolsa bittaga oshirilsin, aks holda ozgartirilmasin.

#include

using namespace std;


int main()

{

int n;



cin>>n;

if(n>0){


n=n+1;

}

cout<

return 0;

}
14.4 xonali son berilgan. Sonni polindromlikka tekshiring(agar son teskarisidan ham oqilganda ozgarmasa u palindrom boladi.)

#include

using namespace std;


int main()

{

int n;



cin>>n;

if(n/1000==n%10 && (n%100)/10==(n%1000)/100){

cout<<"polindrom";

}

else{



cout<<"polindrom emas";

}
return 0;

}
15.Agar k1*k2<1 bolsa y=sqrt(2*k1-7*k2); aks holda y=sqrt(2*k1+7*k2); y=?

#include

#include

using namespace std;


int main()

{

float k1,k2,y;



cin>>k1>>k2;

if (k1*k2<1) {

y=sqrt(2*k1-7*k2);

}

else {



y=sqrt(2*k1+7*k2);

}

cout<
return 0;

}
16.1+1/(2^3)+1/(3^3)+…+1/(n^3)=?

#include
using namespace std;
int main()

{

int n;



float y=0;

cin>>n;


for(float i=1; iy=y+(1/i*i*i);

}

cout<return 0;



}
17.Raqam yozsa hafta kunlarini chiqaradigan dastur tuzing.

#include

using namespace std;
int main()

{

int n;



cin>>n;

switch (n){

case 1 : cout<<"dushanba";break;

case 2 : cout<<"seshanba";break;

case 3 : cout<<"chorshanba";break;

case 4 : cout<<"payshanba";break;

case 5 : cout<<"juma";break;

case 6 : cout<<"shanba";break;

case 7 : cout<<"yakshanba";
}

return 0;

}
18.k ni n marta chiqaradigan dastur tuzing.

#include

using namespace std;
int main()

{

int n,k;



cin>>k>>n;

for(int i=1; i

cout<

}

return 0;



}
19.a ni b ga bolgandagi qoldiqni toping.

#include

using namespace std;
int main()

{

int a,b,q;



cin>>a>>b;

q=a;


while(q>=0){

q=q-b;


}

cout<

return 0;

}
20.Baholarni sifatiga moslashtiring.

#include

using namespace std;


int main()

{

int n;



cin>>n;

switch (n){

case 1 : cout<<"yomon";break;

case 2 : cout<<"qoniqarsiz";break;

case 3 : cout<<"qoniqarli";break;

case 4 : cout<<"yomon";break;

case 5 : cout<<"alo";break;

default : cout<<"xato";



}

return 0;



}

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